Ken Kundert
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Consider a differential LC oscillator. In this case, the output is shunted by a parallel LC resonator. Often the inductor is connected to an ideal voltage source and the capacitor connected to ground. Thus, low frequencies are shorted by the inductor and high frequencies are shorted by the capacitor. If you added a resistance in series with the capacitance to model its finite Q, then you might see a white noise floor, but it will likely be at a very low level, perhaps too low to see. Notice that if you add the resistance in series with the inductance, you would see a noise floor at low frequencies, not at high frequencies.
-Ken
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