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carrier concentration for equilibrium and perturbe (Read 80 times)
jason_class
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carrier concentration for equilibrium and perturbe
Sep 21st, 2003, 4:53am
 
Hello Geoffrey and All,
   
   
    I am not very sure about intrinsic carrier concentration ni.
    For any given temperature, the ni X ni = constant?
    Let's say for Temperature T1,
    the electron concentration carrier is n1
    while hole concentration carrier is p1
    then p1 X n1 = ni X ni
   
   
    Then Temperature T2,
    the electron concentration carrier is n2
    while hole concentration carrier is p2
    then p2 X n2 = ni X ni
   
    then for any Temperature Tx, px X nx is always equal to ni X ni , is
    it correct?
   
    Case 2
    When a p type Silicon(with dopant 10e17) is excite by light, the
    electron concentration n(initial) will increase to some n(excite)
    value.
   
    Is it true that n(initial) X 10e17 = ni X ni
    then n(excite) X 10e17 = ni X ni
   
    So it is true that for any time decay for carrier concentration
    the n(excite1,2,3,..) X 10e17 = ni X ni =n(initial) X 10e17  ?
   
    Thank you for any help given.
   
    rgds
    jason
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Geoffrey_Coram
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Re: carrier concentration for equilibrium and pert
Reply #1 - Sep 23rd, 2003, 1:40pm
 
[quote author=jason_class  link=1064145207/0#0 date=1064145207]
    For any given temperature, the ni X ni = constant?
[/quote]

Let's write ni2(T).  When you write p1 X n1 = ni X ni and then p2 X n2 = ni X ni, you've lost the temperature dependence.  
p(T) X n(T) = ni2(T) always.

Quote:
    When a p type Silicon(with dopant 10e17) is excite by light, the
    electron concentration n(initial) will increase to some n(excite)
    value.
   
    Is it true that n(initial) X 10e17 = ni X ni
    then n(excite) X 10e17 = ni X ni    


No, that's not right, because that would imply n(initial) = n(excite).  

Start with p(T) X n(T) =  ni2(T)

Initially, n(T) = n(initial) and p(T) = 10e17.

After excitation, n(T) = n(excite), but p(T) = ?

-Geoffrey
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jason_class
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Re: carrier concentration for equilibrium and pert
Reply #2 - Sep 26th, 2003, 7:32pm
 
Thank you Geoffrey!
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