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Computing the gain (Read 3098 times)
xn47
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Computing the gain
Jun 13th, 2007, 2:35am  
Is computing the gain of this circuit, using half circuit analysis is just RL/re?

or I have to consider the effect of the current source.. If I use a resistor or any current mirror as my current source ??

What's the effect on the gain?
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carlgrace
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Re: Computing the gain
Reply #1 - Jun 27th, 2007, 6:16am  
This is the simplest diff pair.  gmRl.  Read Gray and Meyer and repent.
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