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Signal exceeds blowup quantity (Read 638 times)
pancho_hideboo
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Re: Signal exceeds blowup quantity
Reply #30 - Sep 17th, 2010, 8:55am
 
Ken Kundert wrote on Sep 17th, 2010, 8:48am:
I am convinced that the circuit contains a negative inductor and so is unstable.
No.
This is "Internal Unstability" problem.
http://www.designers-guide.org/Forum/YaBB.pl?num=1190272820/18#18

You always never admit defect and weak points of Cadence Spectre.

Anyway Cadence Spectre very tends to diverge esepecially in Shooting-Newton.
http://www.designers-guide.org/Forum/YaBB.pl?num=1284058751/4#4

Ken Kundert wrote on Sep 17th, 2010, 8:48am:
In general, using a coupling factor of 1 is almost always wrong.
We can never realize K=1.0.
I always set K < 0.99 even for pure frequency domain analysis such as AC and SP Analyses.

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pancho_hideboo
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Re: Signal exceeds blowup quantity
Reply #31 - Sep 17th, 2010, 9:10am
 
When Rp=0.1ohm, no RHP poles are reported.

But this is not canceling of RHP pole by zero.
This is simply short of negative inductor.
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pancho_hideboo
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Re: Signal exceeds blowup quantity
Reply #32 - Sep 17th, 2010, 9:11am
 
Attached is a result of Transient Analysis of Cadence Spectre.

Here it results in "blowup" after 30nsec for Rp=1.0ohm.
"Rp=0.1ohm" never results in "blowup".

Synopsys HSPICE gives completely same result regarding Transient Analysis.

But results of Pole-Zero analysis are completely different between Cadence Spectre and Synopsys HSPICE.

Pole-Zero analysis of HSPICE have very long history.
On the other hand, Cadence Spectre don't have much history regarding Pole-Zero Analysis.

I also don't think Agilent GoldenGate is reliable since originally it has been developed by Xpedion.
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sheldon
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Re: Signal exceeds blowup quantity
Reply #33 - Sep 17th, 2010, 10:16am
 
Matteo,

  It probably was discussed earlier and I just missed it. Could you
explain why L7, K2/L5/R10, and L8, K3/L7/R7, have eddy current loss
but L6 and L9 do not have eddy current loss? Also are all the mutual
inductances included, there is no L0/L8 or L1/L9 inductance?

                                                                Best Regards,

                                                                    Art Schaldenbrand
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Ken Kundert
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Re: Signal exceeds blowup quantity
Reply #34 - Sep 17th, 2010, 11:40am
 
Quote:
You always never admit defect and weak points of Cadence Spectre.


Pancho Hideboo,
   In this case I am defending Spectre's transient analysis because I believe it is giving the right answer. The circuit contains a negative inductance, of course the circuit is unstable. Spectre correctly reports that instability, and HSpice does not. Your argument that you can somehow make the circuit stable by using either a very large or very small resistor is incorrect. Even the circuit you give to prove your point is unstable, as you will see if you simulate it for 1us (when you reduce the value of the resistor you increase the time constant of the LR circuit, so you have to simulate for longer to see the waveform explode).

-Ken
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