hello,
refer the following pap

http://www.ece.ucsb.edu/Faculty/rodwell/Classes/mixed_signal/Hajimiri_MOTC.pdf
Basically to find the number of zero's you have to find how many infinite value capacitor's will give non zero output.

Thanks,
Raj.

hello,
true. Finding zero's bit tough,unless you are very familiar  with the method what he gave in the pap. He confuse little bit by suing many variables and different terminology. Take a circuit and find total number of capacitors. Let us say 3 so there can be max three zero's. Now short all capacitors and check the output (interested variable it could be voltage or capacitor), if it non zero then 3 zero's. if not short two leave one cap open and check if you have non zero output and repeat the experiment with all other capacitors. Out of 3 trails if you get non zero out put at any time, that indicate 2 zero's. If not short one and open 2 capacitors......

believe me i don't prefer this method to find zero's, however the method open circuit time constant to find poles is much simpler.

Try to read the following.
http://www.ece.ucsb.edu/Faculty/rodwell/Classes/mixed_signal/Cochrun_Grabel_MOTC...

Thanks,
Raj.

dear buddypoor,

CC1 will create a zero due to it's high pass nature, but how abut rest of the capacitors, I have derived but want to know is there any directly method to find?

Br,
Summi