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common collector (Read 853 times)
aman gupta
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common collector
Oct 30th, 2012, 3:08am
 
for the common collector configuration shown i need to find the voltage gain.
The voltage gain formula is AV = (β+1)(ro ll RE)/(rΠ+(β+1)(ro ll RE)
But in the circuit RE is absent . So how do we consider it ??
Nothing is given about the current source.

from the circuit theory i know that the internal impedance of a current source is very high (am i correct ?).

So in this case how do we relate it ?
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raja.cedt
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Re: common collector
Reply #1 - Oct 30th, 2012, 5:18pm
 
hello,
yes you are correct, ideal current  source is infinite resister. So please substitute Re=inf and you get gain=1.

By the way you can explain intutively, due to current source incremental current will be zero, so gm*(Vbe)=0 hence Vbe=0  Vb=Veso unity gain.

Thanks,
Raj.
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aman gupta
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Re: common collector
Reply #2 - Oct 30th, 2012, 9:47pm
 
thanks
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Dan Clement
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Re: common collector
Reply #3 - Oct 31st, 2012, 7:41pm
 
This is a homework problem from Sedra and smith.
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