The Designer's Guide Community
Forum
Welcome, Guest. Please Login or Register. Please follow the Forum guidelines.
Apr 19th, 2024, 1:57pm
Pages: 1
Send Topic Print
What is wrong with this comparator verilog-A model (Read 109 times)
spunky
New Member
*
Offline

Analog Designer

Posts: 4
USA
What is wrong with this comparator verilog-A model
Aug 26th, 2019, 4:25pm
 
I have built a Verilog-A comparator model as shown in the attached picture.

Basically it is just a linear gain stage to process the input voltage delta and then output either high or low with delay.

I am noticing the comparator can give wrong state at output, i.e., the output stuck at low/high when the input delta is obviously positive/negative, especially when one of the input signal is chattering around another. And after that, the output will stuck.

Another thing I have noticed is changing the magnitude of its linear gain sometimes help, but not always.

I am very frustrated about it currently and need comments or suggestions on what the issue could be and how to improve my code for behavior modeling of comparators.

Thanks!
Back to top
 

2019-08-26_16-15-49.png
View Profile spunky   IP Logged
spunky
New Member
*
Offline

Analog Designer

Posts: 4
USA
Re: What is wrong with this comparator verilog-A model
Reply #1 - Aug 26th, 2019, 4:28pm
 
Not sure how to attach the 2nd picture showing the simulated results.
But here it is.
Back to top
 

2019-08-26_16-20-49.png
View Profile spunky   IP Logged
Ken Kundert
Global Moderator
*****
Offline



Posts: 2384
Silicon Valley
Re: What is wrong with this comparator verilog-A model
Reply #2 - Aug 26th, 2019, 6:50pm
 
Seems like a lot of complexity for a comparator model. I recommend that you start simple, get that working, and then only add what you really need. A good starting point would be the Verilog-A comparator on the Verilog-AMS page.

-Ken
Back to top
 
 
View Profile WWW   IP Logged
Geoffrey_Coram
Senior Fellow
******
Offline



Posts: 1998
Massachusetts, USA
Re: What is wrong with this comparator verilog-A model
Reply #3 - Aug 28th, 2019, 7:09am
 
Rather than two cross statements, trying to catch it as it goes one way or the other, I'd use one cross statement for timestep control:
Code:
    @(cross((V(inp, inm) - vthres/comp_gain)))
	  ; // null statement 



and then have a plain if statement to set out_val and del:
Code:
    if (V(inp, inm) > vthres/comp_gain) begin
	  out_val = 1;
	  del = comp_delay_r;
    end else begin
	  out_val = 0;
	  del = comp_delay_f;
    end 



I'd have to read up on what the LRM says happens if you happen to hit the threshold exactly: is this a cross event? in which direction? And then I'd have to wonder if the simulator implemented it correctly.
Back to top
 
 

If at first you do succeed, STOP, raise your standards, and stop wasting your time.
View Profile WWW   IP Logged
Hesham
New Member
*
Offline



Posts: 6

Re: What is wrong with this comparator verilog-A model
Reply #4 - Aug 30th, 2019, 10:32am
 
Back to top
 
 
View Profile   IP Logged
Pages: 1
Send Topic Print
Copyright 2002-2024 Designer’s Guide Consulting, Inc. Designer’s Guide® is a registered trademark of Designer’s Guide Consulting, Inc. All rights reserved. Send comments or questions to editor@designers-guide.org. Consider submitting a paper or model.