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Design >> Analog Design >> linear time-based events in verilog-ams
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Message started by steve_mac on Nov 23^rd, 2005, 3:42am

Title: linear time-based events in verilog-ams
Post by steve_mac on Nov 23^rd, 2005, 3:42am

hi i'm new with verilog-a and i'd like to ask how do i model a linear time-based event ?

example: a linear voltage drop :

V = -3.4545 * time + Vdd

How do i put the "time" here in verilog-a syntax?

Thanks, appreciate the help.

Title: Re: linear time-based events in verilog-ams
Post by Jess Chen on Nov 23^rd, 2005, 9:57am

Try

V = -3.4545*$abstime + Vdd.

If you want incremental time, you can use

t = idt(1,0,assrt).

When assrt is nonzero, t remains at zero. When assrt is zero, t = incremental time. The only caution is that depending on the application, you may have to use conservative numerical options.

-Jess

Title: Re: linear time-based events in verilog-ams
Post by steve_mac on Nov 23^rd, 2005, 6:44pm

Hi Jess,

Thanks :)