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https://designers-guide.org/forum/YaBB.pl Modeling >> Behavioral Models >> OTA macro-model https://designers-guide.org/forum/YaBB.pl?num=1133267157 Message started by Visjnoe on Nov 29th, 2005, 4:25am |
Title: OTA macro-model Post by Visjnoe on Nov 29th, 2005, 4:25am Hi, maybe this topic is a bit too trivial for some of you, nevertheless... Let's assume I want to model (Verilog-AMS, so no SPICE macro-modeling) a CMOS OTA with the dominant pole at its output (e.g. symmetrical CMOS OTA). In most code snippets I have seen, most people tend to put a Laplace transfer function inside the OTA model and include the output impedance using a real parameter, finally using a statement as this: I(outp,vss) <+ V(outp,vss)/rout My question is as follows: if the capacitive load (SPICE primitive) of the AMS-model of the OTA changes, will the output pole of the overall model change? Or: thus the real parameter 'rout' interact with a SPICE primitive to form a pole 1/(2*pi*rout*C), which can, e.g. be seen in an AC analysis? Kind Regards Peter |
Title: Re: OTA macro-model Post by sheldon on Nov 29th, 2005, 9:13pm Peter, Yes the pole will change, as it should. Remember, Op-Amps are supposed to low output impedenace and insensitive to output loading. While an OTA is high output impedance and sensitive to output loading. Best Regards, Sheldon |
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