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https://designers-guide.org/forum/YaBB.pl Design >> Mixed-Signal Design >> how to implement 1/(1-a*z^(-1)) with SC circuit https://designers-guide.org/forum/YaBB.pl?num=1206966312 Message started by baohulu on Mar 31st, 2008, 5:25am |
Title: how to implement 1/(1-a*z^(-1)) with SC circuit Post by baohulu on Mar 31st, 2008, 5:25am hi, all in SC circuit, we can always see the implement of a/(1-z^(-1)), while, can it implement 1/(1-a*z^(-1)), where a is not equal to 1? if there is some reference, please tell me thanks |
Title: Re: how to implement 1/(1-a*z^(-1)) with SC circui Post by pancho_hideboo on Mar 31st, 2008, 5:51am baohulu wrote on Mar 31st, 2008, 5:25am:
For me, complete integral a/(1-z^(-1)) is rare. Rather incomplete integral 1/(1-a*z^(-1)) is common. So realize it as incomplete integral. Also we can realize "a" as complex number. |
Title: Re: how to implement 1/(1-a*z^(-1)) with SC circui Post by baohulu on Mar 31st, 2008, 6:49pm then how to implement it ? use input forward feedthrough to the input? however, in the SC bandpass sigma delta adc, the resonator is usually implemented use the a/(1-z^(-1)) or a*z^(-1)/(1-z^(-1)), rather than 1/(1-a*z^(-1)) , and why? |
Title: Re: how to implement 1/(1-a*z^(-1)) with SC circui Post by Berti on Mar 31st, 2008, 11:14pm Hi, a/(1-z^(-1)) or a*z^(-1)/(1-z^(-1)) are integrators without and with delay, respectively. Integrators are relatively straight-forward to be implemented as a SC circuit. 1/(1-a*z^(-1)) is also called leaky-integrator (for a<1). In fact, most circuit implementations have such a transfer function. Due to infinte gain of amplifiers etc., charge-transfer won't be ideal and you will loose a small amount of charge during each phase. This charge-loss will result in a a transfer function equal to 1/(1-a*z^(-1)), where a can be approximated as 1-1/(Gain of amplifier). Hope this helps, cheers |
Title: Re: how to implement 1/(1-a*z^(-1)) with SC circui Post by pancho_hideboo on Mar 31st, 2008, 11:54pm baohulu wrote on Mar 31st, 2008, 6:49pm:
The followings are not best reference, but might be helpful for you. In [2], 1st IIR is implemented as incomplete integral(leaky integral). [1] AUTHORS: Stephen A. Jantzi, Kenneth W. Martin, and Adel S. Sedra TITLE: Quadrature bandpass ΔΣ modulation for digital radio ISSUE: IEEE Journal of Solid-State Circuits, vol. 32, pp. 1935 - 1950, December 1997 [2] TITLE: A discrete-time bluetooth receiver in a 0.13μm digital CMOS process ISSUE: IEEE International Solid-State Circuits Conference, vol. XLVII, pp. 268 - 269, February 2004 baohulu wrote on Mar 31st, 2008, 6:49pm:
See above [1]. |
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