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https://designers-guide.org/forum/YaBB.pl Design >> RF Design >> calculate the input impedance for cmos https://designers-guide.org/forum/YaBB.pl?num=1209653115 Message started by wwm101 on May 1st, 2008, 7:45am |
Title: calculate the input impedance for cmos Post by wwm101 on May 1st, 2008, 7:45am why the follow circuit diagram which input impedance equal to 1/(gm1a+gm1b) in the radio frequency? this problem confuse me long time .pleas help! thank you for your attention! |
Title: Re: calculate the input impedance for cmos Post by pancho_hideboo on May 1st, 2008, 9:30am wwm101 wrote on May 1st, 2008, 7:45am:
If it is not in the radio frequency, it is very simple. Transconductance of inverter is Gm=gm1a+gm1b. So input admittance Yin seeing right at node X is like following. Yin=GF*(YL+Gm)/(YL+GF) where GF is feedback conductance for self bias, so GF=1/R, R is resistor between X and Y. YL is load admittance at node Y. If ZL=1/YL=infinity, Yin=Gm=gm1a+gm1b. If ZL=1/YL=0, Yin=GF=1/R. If GF=0, Yin=0. So if impedance seeing right at node Y is enough high, ZL >> 1/Gm, 1/GF=R an input impedance Zin seeing right at node X will be 1/Gm=1/(gm1a+gm1b). For the radio frequency, this is not true. |
Title: Re: calculate the input impedance for Post by wwm101 on May 2nd, 2008, 12:37am TO:pancho_hideboo thank you very much for your explain. |
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