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https://designers-guide.org/forum/YaBB.pl Design >> Analog Design >> basics Question https://designers-guide.org/forum/YaBB.pl?num=1331933966 Message started by raja.cedt on Mar 16th, 2012, 2:39pm |
Title: basics Question Post by raja.cedt on Mar 16th, 2012, 2:39pm hello, this is some purely theory based and graduate level question. If there any LC filter and if i apply some dc voltage at the input, the peak-voltage at the cap is 2 times the input voltage. I have derived and got ans, but is there any way understand intuitively without doing math. thanks, raj. |
Title: Re: basics Question Post by RobG on Mar 17th, 2012, 9:15am Do you mean that you are applying a stepped input? |
Title: Re: basics Question Post by raja.cedt on Mar 17th, 2012, 11:09am yes.... |
Title: Re: basics Question Post by RobG on Mar 17th, 2012, 5:13pm I'm rusty, but I get the answer to be a sine wave with amplitude Vstep/sqrt(LC). Where do you come up with the number 2? |
Title: Re: basics Question Post by HdrChopper on Mar 17th, 2012, 8:34pm A step input will create an oscillation whose amplitude will depend on the values of L and C around whatever DC level the voltage step has. thus does not have to be 2x |
Title: Re: basics Question Post by raja.cedt on Mar 18th, 2012, 1:51am hello all, i donno how you guys solved, but i have used normal circuit theory and i got it is v(1-cos(w*t)), so it's peak is 2*v, in fact this is quite common result in transmission lines also. Thanks, Raj. |
Title: Re: basics Question Post by RobG on Mar 18th, 2012, 9:20am raja.cedt wrote on Mar 18th, 2012, 1:51am:
Oh hell, I did the impulse response, not step response. I now get the same answer as you. I guess chopper and I may have to migrate to management soon before we rust completely. I guess you could say that all of the energy will slosh back and forth between L and C so the minimum energy in each will be zero at some point in time. So that explains the bottom peak being equal to zero. Furthermore, we could say the midpoint (average value) must be v since the average value of the input must equal the average value of the output given the inductive (DC) coupling (and also the steady state solution with a series resistance that goes to zero will be v). Finally, we know the answer is a sinusoid that must start at zero... It is easy to say such things once you know the answer ;) |
Title: Re: basics Question Post by HdrChopper on Mar 19th, 2012, 7:53am RobG wrote on Mar 18th, 2012, 9:20am:
I'm working on that already :P My mistake was that I always thought of a RLC response, not a purely LC one (do not know why since the question was clear from very beginning! So Raja you were correct! |
Title: Re: basics Question Post by Vladislav D on Mar 19th, 2012, 1:14pm For the lazy persons (like me) http://www.lccircuits.com/ |
Title: Re: basics Question Post by raja.cedt on Mar 19th, 2012, 3:06pm hey Vladislav D, cool man...interesting website. Keep posting this type of websites. Thanks, Raj. |
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