The Designer's Guide Community Forum
https://designers-guide.org/forum/YaBB.pl
Simulators >> RF Simulators >> question about input referred noise
https://designers-guide.org/forum/YaBB.pl?num=1196391077

Message started by Julian18 on Nov 29th, 2007, 6:51pm

Title: question about input referred noise
Post by Julian18 on Nov 29th, 2007, 6:51pm

Hi,  there:
     suppose I have a circuit, and I do three simulations as described below
1)  add a port as input probe, set its resistance, say 50 , and run noise analysis, now I can get input referred noise voltage from the result, call it NP.
2)  replace the port with a voltage source in series with a 50Ohms resistor, run noise analysis, get the input referred noise voltage ,call it NV.
3)  replace the voltage and series resistor with a current source in parallel with a 50Ohms resistor, run noise analysis, get the input referred noise current, call it NI.
 Now can any one tell me what's the relationship btw these three quantities.

Thanks.

Title: Re: question about input referred noise
Post by aaron_do on Nov 30th, 2007, 1:45am

Hi,

input referred noise is just the output noise power divided by the power gain. If you measure the output noise is V^2/Hz, and you want to refer it back to a voltage, divide by (V/V)^2. If you measure in terms of output current ^2 then divide by gm^2. Your 50 ohm resistor is just complicating things since you don't need it to find the input referred noise (unless its part of the circuit). In fact you have to subtract its noise contribution to find the input referred noise. For example, if you have a port and you measure NF, the IRN can be found from,

NF=(IRN+kT50)/kT50

where IRN is in V^2/sqrt(Hz)
hope it helps,
Aaron

Title: Re: question about input referred noise
Post by Julian18 on Nov 30th, 2007, 4:28am


aaron_do wrote on Nov 30th, 2007, 1:45am:
Hi,

input referred noise is just the output noise power divided by the power gain. If you measure the output noise is V^2/Hz, and you want to refer it back to a voltage, divide by (V/V)^2. If you measure in terms of output current ^2 then divide by gm^2. Your 50 ohm resistor is just complicating things since you don't need it to find the input referred noise (unless its part of the circuit). In fact you have to subtract its noise contribution to find the input referred noise. For example, if you have a port and you measure NF, the IRN can be found from,

NF=(IRN+kT50)/kT50

where IRN is in V^2/sqrt(Hz)
hope it helps,
Aaron


Hi, Aaron:
    thank your for your information.the reason of adding the resistor is that, I just want to see the relationship of these three quantities, as spectre reference sais, when input port is used as input probe, the noise associated with the port resistance will contribute to the total output noise, so I intentionally add resistors in two other situations to equate the noise source number in the circuit.  and i expect that if we ignore the correlation btw the  noise voltage and noise current, the following relation may hold:
                 N_current^2*50^2+N_voltage^2 = N_port^2  
but i can not arrive at this relation from the simulation result. So I asked the question.

Any other information?



Title: Re: question about input referred noise
Post by didac on Nov 30th, 2007, 5:21am

Hi,
Have you checked that both port & simulator temperatures are the same?
Hope it helps,

The Designer's Guide Community Forum » Powered by YaBB 2.2.2!
YaBB © 2000-2008. All Rights Reserved.