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Design Languages >> Verilog-AMS >> Creating two pulses with different rise times using two transition operators
https://designers-guide.org/forum/YaBB.pl?num=1454307977

Message started by Rosh on Jan 31^st, 2016, 10:26pm

Title: Creating two pulses with different rise times using two transition operators
Post by Rosh on Jan 31^st, 2016, 10:26pm

Hello all,

I have to generate two pulses, each with different rise times.

This is my code

Code:

`include "disciplines.vams"

module vdriver(out);
parameter real td = 10n;
parameter real tt = 10n;

output out;
voltage out;
real Vout, tend,rst;

analog
begin

@(timer(0))
begin
Vout=0;
end

@(timer(20n))
begin
Vout=5;
end

@(timer(40n))
begin

Vout=3;
end

@(timer(60n))
begin

Vout=5;
end

V(out)<+transition(Vout,0,td,tt); //Rise=Fall=10n

end

endmodule

However, I'd like the second the second pulse to have a different rise/fall time.
If I add a second transition operator however, the entire waveform goes haywire. Any recommendation to solve this?

Title: Re: Creating two pulses with different rise times using two transition operators
Post by Ken Kundert on Feb 1^st, 2016, 10:48am

You are already changing the voltage of each transition. Use the same technique to change the transition time.

In otherwords, make tt a variable that you set when you set Vout.

-Ken