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jcpu2006 Junior Member Offline Posts: 19 Hsinchu	1V-->3V boost Jul 12^th, 2006, 9:16pm Dear Sir: I've a 2.4V-->3.3V boost dcdc and next target would be 1v-->3V dcdc what should I do? Build a 0.7V BGR with VDD down to 1V?? that doesn't seems to help so much...
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loose-electron

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Re: 1V-->3V boost
Reply #1 - Aug 3^rd, 2006, 4:19pm

They are called "charge pumping circuits" where you use switches to dump charge onto a capacitor to get above the power supply voltage.

In some cases, you can use charge pumps, to drive another charge pump.

Example: 1V power, can get you to a around a 1.8V on a capacitor. Then you use that to power another pump that get you up to around 3V or so.

Take a look in the IEEE JSSC - there should be some stuff there on the topic.

Here is a good introduction:

http://www.eecg.utoronto.ca/~kphang/ece1371/chargepumps.pdf

that should get you started in the right direction.

Jerry

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RobG

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Re: 1V-->3V boost
Reply #2 - Oct 16^th, 2006, 10:52am

My paper in the August 2006 IEEE Journal of Solid State Circuits has a topology that creates its own reference and will work down to 1V. I tried to make it understandable to people without a lot of charge pump experience, so it may be helpful to you.

http://ieeexplore.ieee.org/iel5/10489/33245/01568778.pdf?isnumber=&arnumber=1568...

rg

edit... sorry, the above link was for the CICC version. The JSSC article is here.

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darrenxyz

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taiwan

Re: 1V-->3V boost
Reply #3 - Nov 28^th, 2006, 7:55pm

after dcdc startup, you can connected BGR to dcdc output,so you can provide 3.3v power to the BGR,
not by battery power!!

jcpu2006 wrote on Jul 12^th, 2006, 9:16pm:

Dear Sir:

I've a 2.4V-->3.3V boost dcdc
and next target would be 1v-->3V dcdc
what should I do?

Build a 0.7V BGR with VDD down to 1V??
that doesn't seems to help so much... Sad

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