I have read the article by Ken Kundert 'Hidden States in SpectreRF' but could not get rid of the hidden states for the following code. For the PSS analysis it generates error for variable 'i' for hidden state.
Please help!

`include "constants.vams"
`include "disciplines.vams"

module SAR_CL(vin,vclk,vd9,vd8,vd7,vd6,vd5,vd4,vd3,vd2,vd1,vd0,vdb9,vdb8,vdb7,vdb6,vdb5
,vdb4,vdb3,vdb2,vdb1,vdb0);
input vin,vclk;
output vd9,vd8,vd7,vd6,vd5,vd4,vd3,vd2,vd1,vd0,vdb9,vdb8,vdb7,vdb6,vdb5,vdb4,vdb3,vdb2,
vdb1,vdb0;
electrical vin,vclk,vd9,vd8,vd7,vd6,vd5,vd4,vd3,vd2,vd1,vd0,vdb9,vdb8,vdb7,vdb6,vdb5,vdb4,v
db3,vdb2,vdb1,vdb0,hold;

parameter real trise  = 100p  from [0:inf);
parameter real tfall  = 100p  from [0:inf);
parameter real tdel   = 10p   from [0:inf);
parameter real vtrans = 0.6 from [0:inf);

real comp_out;real result[0:10];
real resultb[0:10];
integer i;

  analog
  begin
     @ (initial_step)
     begin
        i = 10;
      result[10] = 1.2;
      result[9]  = 0;
      result[8]  = 0;
      result[7]  = 0;
      result[6]  = 0;
      result[5]  = 0;
      result[4]  = 0;
      result[3]  = 0;
      result[2]  = 0;
      result[1]  = 0;
      result[0]  = 0;
     end
     @ (cross(V(vclk) - vtrans, +1))
     begin
       comp_out = V(vin);
     if (comp_out > vtrans)
     begin
        result[i]    = 1.2;
        resultb[i]   = 0.0;
        result[i-1]  = 1.2;
        resultb[i-1] = 0.0;
     end
     else
     begin
        result[i]    = 0.0;
        resultb[i]   = 1.2;
        result[i-1]  = 1.2;
        resultb[i-1] = 0.0;
     end
     
       i = i - 1;
     if (i <= 0)
     begin
        i = 10;
        result[10] = 1.2;
        result[9]  = 0;
        result[8]  = 0;
        result[7]  = 0;
        result[6]  = 0;
        result[5]  = 0;
        result[4]  = 0;
        result[3]  = 0;
        result[2]  = 0;
        result[1]  = 0;
     end
     else
     begin
        i = i;
     end              
     end

     V(vd9)  <+ transition( result[10], tdel, trise, tfall );
     V(vd8)  <+ transition( result[9],  tdel, trise, tfall );
     V(vd7)  <+ transition( result[8],  tdel, trise, tfall );
     V(vd6)  <+ transition( result[7],  tdel, trise, tfall );
     V(vd5)  <+ transition( result[6],  tdel, trise, tfall );
     V(vd4)  <+ transition( result[5],  tdel, trise, tfall );
     V(vd3)  <+ transition( result[4],  tdel, trise, tfall );
     V(vd2)  <+ transition( result[3],  tdel, trise, tfall );
     V(vd1)  <+ transition( result[2],  tdel, trise, tfall );
     V(vd0)  <+ transition( result[1],  tdel, trise, tfall );

     V(vdb9) <+ transition( resultb[10], tdel, trise, tfall );
     V(vdb8) <+ transition( resultb[9],  tdel, trise, tfall );
     V(vdb7) <+ transition( resultb[8],  tdel, trise, tfall );
     V(vdb6) <+ transition( resultb[7],  tdel, trise, tfall );
     V(vdb5) <+ transition( resultb[6],  tdel, trise, tfall );
     V(vdb4) <+ transition( resultb[5],  tdel, trise, tfall );
     V(vdb3) <+ transition( resultb[4],  tdel, trise, tfall );
     V(vdb2) <+ transition( resultb[3],  tdel, trise, tfall );
     V(vdb1) <+ transition( resultb[2],  tdel, trise, tfall );
     V(vdb0) <+ transition( resultb[1],  tdel, trise, tfall );

  end

endmodule

you are using the variable i to "remember" the value over time.. THIS IS EXACTLY what causes a hidden state.
Save NO information , keep no HISTORY in a VARIABLE..
- instead use a capacitor as an integrator to store the information you want to keep. since a capacitor is Electrical - spectreRF can "see" it and there is no hidden state..
--
good luck