boe
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lbtroy, In general, hard switching between voltage sources and current sources often causes convergence problems. This also applies to nodes with infinite impedance (i=0).
Further, for V(tune_mode) < min(V(avdd), V(dvdd))-0.1, ftunem is HiZ, and ftunem_filt is shorted to ftunem_filt, while for V(tune_mode) > max(V(avdd), V(dvdd))-0.1, ftunem is at 0.65 V, but ftunem_filt is HiZ... I do not see why you need two nodes here. I would connect ftunem/p directly to the loopfilter and put the switch in the pump (by defining output current appropriately)... BOE
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