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zero diagonal found in Jacobian error (Read 2058 times)

lbtroy

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Posts: 1

zero diagonal found in Jacobian error
Oct 16^th, 2009, 10:15am

Hi all,

Currently I have a chargepump that charges to a loop filter(made out of verilog ams coded caps and resistors) when a switch opens. As it open, my outputs blows up to almost infinity. Does anyone know if there is a good way to resolve this?

////////////////////////////////////////////////////////////////////////////////
///////////////////
at the chargepump end: i have

if(V(tune_mode) < (dvdd - 0.1))
I(ftunem,avss) <+ 0;
else
V(ftunem,avss) <+ 0.65;
if(V(tune_mode) < (dvdd - 0.1))
I(ftunep,avss) <+ 0;
else
V(ftunep,avss) <+ 0.65;
////////////////////////////////////////////////////////////////////////////////
//////////////////////
at the loop filter end: i have
if(V(tune_mode) < (V(avdd) - 0.1))
V(ftunem,ftunem_fil) <+ 0 ;
else
I(ftunem,ftunem_fil) <+ 0;
if(V(tune_mode) < (V(avdd) - 0.1))
V(ftunep,ftunep_fil) <+ 0 ;
else
I(ftunep,ftunep_fil) <+ 0;

Thank you

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boe

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Posts: 615

Re: zero diagonal found in Jacobian error
Reply #1 - Oct 16^th, 2009, 10:38am

lbtroy,
In general, hard switching between voltage sources and current sources often causes convergence problems. This also applies to nodes with infinite impedance (i=0).

Further, for V(tune_mode) < min(V(avdd), V(dvdd))-0.1,
ftunem is HiZ, and ftunem_filt is shorted to ftunem_filt,
while for V(tune_mode) > max(V(avdd), V(dvdd))-0.1,
ftunem is at 0.65 V, but ftunem_filt is HiZ...
I do not see why you need two nodes here. I would connect ftunem/p directly to the loopfilter and put the switch in the pump (by defining output current appropriately)...
BOE

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