altaj
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After hammering away all day with a novice's knowledge of verilog-A, I have a great sense of accomplishment at getting my modules to work, and match the transistor circuits very well.
My question: Is there a way to simplify the following lines from my code?
@(cross(V(rb) - vth, -1)) count=0;
@(cross(V(rb) - vth, -1)) n=0;
Can they be combined so that there is only one "@(cross(V(rb) - vth, -1))" to service both "=0's"?
Thanks,
John
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basic verilog-A syntax question (Read 2292 times)