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Mar 28th, 2023, 6:11am
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 Conductor linear model (Read 849 times)
 ranjang Junior Member Offline Posts: 13 india Conductor linear model Sep 11th, 2014, 8:10pm   I am new to V-AMS .In the V-AMS LRm section  5.6.3 Resistor and conductorWe have following code for Conductance linear model.module my_conductor(p,n); inout p, n;electrical p,n;parameter real G=1; branch (p,n) cond;analog beginI(cond) <+ G * V(cond);endendmoduleWhy we call this as a model for linear conductance .As we have G as always fixed or as paramter.It looks like a current source model.Also In place of analog begin--endIf I replace it with analog block how does it make difference.Thanks, Back to top ,GAURAV   IP Logged
 boe Community Fellow Offline Posts: 615 Re: Conductor linear model Reply #1 - Sep 12th, 2014, 1:11am   ranjang wrote on Sep 11th, 2014, 8:10pm:...Why we call this as a model for linear conductance . ... Perhaps because the current is proportional to the voltage?- B O E Back to top IP Logged
 Geoffrey_Coram Senior Fellow Offline Posts: 1997 Massachusetts, USA Re: Conductor linear model Reply #2 - Mar 27th, 2015, 5:08am   A current source would have I(branch) <+ iout; but as boe noted, this model's current is proportional to the voltage.analog begin...endis an analog block, so your second question doesn't make any sense. Back to top If at first you do succeed, STOP, raise your standards, and stop wasting your time.   IP Logged
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