achim.graupner
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Hi Ken,
I tried to use the swept PSS, but I suppose I did not have understood what is going on during a PSS: I tried to use a very simple circuit: an ideal resistor, an ideal capacitor and an ideal inductor with a series resistor that are connected in parallel.
V0 (net1 0) vsource dc=5 mag=1 type=sine ampl=1 freq=frq L0 (net1 net8) inductor l=18m C0 (net1 0) capacitor c=10p R1 (net8 0) resistor r=1 R0 (net1 0) resistor r=100K ac ac start=10k stop=10M annotate=status sweeppss sweep param=frq start=10k stop=10M dec=20 { pss pss fund=frq harms=0 errpreset=moderate annotate=status
pac pac sweeptype=relative start=frq maxsideband=0 + annotate=status }
now I've done both: an AC-analysis and a swept PSS and measured the current flowing out V0. In AC-simulation the current is, as expected at minimum at about 280kHz. The PSS results in an output current of 5A which is comparable to the DC-operating point. As I am interested in the AC amplitude is run a subsequent PAC. For PAC I've ploted the source's current, as sweep I've used "frequency" and as signal level I' used peak. In this case the results of the AC and the swept PSS/PAC analysis are identically. However, if I use "variable" as sweep value, the resonant frequency is to be found at a different location. Any explanations for this behaviour?
Thanks in advance, - achim
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