jbdavid
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My general model of a DC-DC converter assumes an input voltage from a thevinen eq. source and has a Thevinen eq output.. so my input current is a function of the input voltage, the transfer function (ie Vout = 8*Vin), Pout = H*Pin, where H<1.0 and Pout = Vout*Iout.. Rout is a function of the clock rate and Capacitance ,, so you know Vout, and Rout, the simulator can figure out Iout from your load circuit.. when you know Iout, you can calculate Pout, and thus Pin, and thus Iin .. then your simulator can determine what your operating point is.. So V(outi) <+ 8 * V(in); V(out,outi) <+ I(out,outi)*Rout;// need to pick the right current direction Pout = I(out,outi)*V(outi); Pin = H*Pout; I(in) <+ Pin/V(in) + Ibias; // its probably good to ensure the current (IN) also includes a fixed bias component. Jonathan
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