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laplace transform (Read 838 times)
Tommy
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laplace transform
Feb 15th, 2007, 7:00am
 
Hi,
How to implement a function like H(s) = 1 + as + bs^2 ?
laplace_nd in cadence spectre exits complaining that the order of denominator is not  same as numerator order.

Thanks
Tom
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Geoffrey_Coram
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Re: laplace transform
Reply #1 - Feb 15th, 2007, 11:51am
 
Are you sure you don't want H(s) = 1/ (1 + as + bs^2) ?
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Ken Kundert
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Re: laplace transform
Reply #2 - Feb 15th, 2007, 1:25pm
 
In case you want your original transfer function rather than Geoffrey's, you can get it by using the laplace function to implement a voltage-to-current converter with Geoffrey's, and then place it in the feedback path of an ideal opamp configured as an inverting amplifier. That will act to invert the transfer function.

-Ken
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mg777
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Re: laplace transform
Reply #3 - Feb 18th, 2007, 10:52pm
 

To continue on the denominator theme, add a D(s) such that H'(s) = H(s)/D(s) has a bandwidth 3X larger than the signal you're emphasizing. A good choice for D(s) would be a 3rd order Bessel.

M.G.Rajan
www.eecalc.com

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