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Cgd in miller effect (Read 2338 times)

RobertZ Community Member Offline the art of analog Posts: 55 San Diego, CA	Cgd in miller effect Jul 10^th, 2007, 11:56pm Hi, all, In spectre's simulation result, there are Cgd and Cdg in the operation print out, and they are different (sometimes, by a lot). Which one should be used for miller effect? \|Av\|Cgd or \|Av\|Cdg shows up at the gate? Thanks, Robert
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boe

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Re: Cgd in miller effect
Reply #1 - Jul 11^th, 2007, 1:32am

Hi RobertZ,
I think Yawei's post helps here:
ywguo wrote on Jul 7^th, 2007, 12:20am:

Hi,
Assume you are using BSIM 3v3 model, please take a look at the definition using spectre -h bsim3v3.
Here, cdg is ΔQd/ΔVg, cgd is ΔQg/ΔVd, cgs is ΔQg/ΔVs. So it is not curious to see minus capacitance.
Yawei

So you need cgd...

Hope this helps
BOE

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