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Spectre diiference in reltol? (Read 4034 times)
bernd
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Spectre diiference in reltol?
May 26th, 2008, 1:46am
 
Hi,

This is a specific tool question about Cadence Spectre  in the
Analog Environment, but maybe some of the Gurus here have
seen this and know an explanation.

 I discovered a strange thing.
In Spectre I always see that the value of reltol reported in the
spectre.out file is 1 decimal power smaller than the
specified reltol value in the simulation options.

Is there any explanation for this behaviour?
And which is the reltol value the simulator is using?

Thanks in advance,
Bern d
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reltol_diff.jpg

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byang
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Re: Spectre diiference in reltol?
Reply #1 - May 26th, 2008, 8:07am
 
Hi, Bernd,

This is caused by errpreset=conservative. When errpreset=conservative in a tran statement, the used reltol in that tran analysis will be equal to 0.1 * the reltol specified in options.

When errpreset=liberal or moderate, the reltol doesn't change.

byang
http://www.gemini-da.com
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bernd
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Re: Spectre diiference in reltol?
Reply #2 - May 26th, 2008, 8:49am
 
Thanks  ;)
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