The DC operating point around which the AC analysis linearises the equations will have 0V between node1 and node0 with your example source. Then, the response of these linearised equations to a 1V (the AC source) stimulus across node1 and node0 will be computed, and you can then see the results of the transfer functions of these linearised equations to other nodes in the circuit.
If you're hoping to use a voltage source to break/close a loop, then that won't work. You can use AC resistors for that (or the "switch" component in spectre).
There's a very good coverage of this in Ken's book
http://www.designers-guide.org/Books/#Kundert-1995 - you can see the first few pages of the AC chapter if you follow the links on that page.
It's still not terribly clear to me what you're trying to do here.
There are also a lot of posts in this forum talking about analysing stability - you might want to use the Forum search function.
Regards,
Andrew.