The Designer's Guide Community
Forum
Welcome, Guest. Please Login or Register. Please follow the Forum guidelines.
Aug 16th, 2024, 2:25am
Pages: 1
Send Topic Print
replacing the ideal tail current in a differential pair with active transistors (Read 3532 times)
salma shabayek
New Member
*
Offline



Posts: 6

replacing the ideal tail current in a differential pair with active transistors
Jun 12th, 2009, 1:27am
 
Dear all,
I'm having a trouble in replacing the ideal tail current in the differential pair with an nmos current sourc transistors mirrored to an nmos diode connected transistor.
I did so by placing the nmos transistor with double the size of the nmos input transistor but I dont get amplification.
before placing the tail current I had large gain but now I dont..
so please if anyone knows what's the problem please tell me.

I also have another question ; since I'm working with 1uA current per branch and from using the current density charts and gm/id curves in Spectre I always get (W/L) ratio< 1

Is that acceptable???
thank you alooooooottttttttttttt
Back to top
 

scematic2.png
View Profile   IP Logged
subgold
Community Member
***
Offline



Posts: 97

Re: replacing the ideal tail current in a differential pair with active transistors
Reply #1 - Jun 12th, 2009, 2:47am
 
it is because your dc biasing point of the input transistors are too low.
Back to top
 
 
View Profile   IP Logged
raja.cedt
Senior Fellow
******
Offline



Posts: 1516
Germany
Re: replacing the ideal tail current in a differential pair with active transistors
Reply #2 - Jun 12th, 2009, 3:05am
 
hi,
   did you probe the tail transistor drain?i think it is  at very low hence tail transistor is in triode so degeneration. I am surprising how cum you are working with 1u, what you will get 1u?

Thanks,
rajasekhar.
Back to top
 
 
View Profile WWW raja.sekhar86   IP Logged
oermens
Community Member
***
Offline



Posts: 86

Re: replacing the ideal tail current in a differential pair with active transistors
Reply #3 - Jun 12th, 2009, 4:21am
 
In order to achieve IdsNM1=IdsNM4 you need

(W/L)NM1=(W/L)NM4
VgsNM1=VgsNM4
VdsNM1=VdsNM4

you are probably not meeting the last criteria. if you can spare the headroom, use cascode or wilson current mirror. refer to razavis analog book.

also I think it is difficult to achieve 1uA from tail transistor in saturation. you might have to consider weak inversion current mirror. but this suffers from poor matching... see this paper: http://ieeexplore.ieee.org/xpls/abs_all.jsp?arnumber=4263360
Back to top
 
 
View Profile   IP Logged
ic_engr
Senior Member
****
Offline



Posts: 135

Re: replacing the ideal tail current in a differential pair with active transistors
Reply #4 - Jun 12th, 2009, 8:36am
 
Salma,

What is your supply voltage.  What is the VT of the NM0 & NM8.?
You definitely need to raise the DC levels on the diff pair (NM0 & NM8). Remember, the lower the DC on the diff pair, the lower VDS will be on the current source NM4 in question.

More importantly, looking at the model names (n_12_hs130e), it seems you are using high speed devices, which will definitely suffer with poor output impedance thus excerbating your problem.

Good luck.
Back to top
 
 
View Profile   IP Logged
salma shabayek
New Member
*
Offline



Posts: 6

Re: replacing the ideal tail current in a differential pair with active transistors
Reply #5 - Jun 13th, 2009, 3:33am
 
ok ...thank you alll soooo muchhh
Back to top
 
 
View Profile   IP Logged
Pages: 1
Send Topic Print
Copyright 2002-2024 Designer’s Guide Consulting, Inc. Designer’s Guide® is a registered trademark of Designer’s Guide Consulting, Inc. All rights reserved. Send comments or questions to editor@designers-guide.org. Consider submitting a paper or model.