aamar
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Germany
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you can simply understand this amplifier as 3 stages of amplification.
the first is the M1 transistor which sees at its drain a small signal voltage (e.g. V1) equal to the Vi multiplied by the M1's gain (A1) and is equal to gm1xro1.
This signal V1 is amplified again by Av and applied to the gate of M2, so the gate voltage of M2 is simply V1xAv
The third stage is M2 which has a Gate Source voltage equal to V2-V1, however V2 is much larger than V1 so that it can be ignored for simplification. Then the drain voltage of M2 in this case is V2 multiplied with M2's gain (A2) which is nothing else than gm2xro2.
As a result the Vo is then VixA1xAvxA2, and hence the A=Vo/Vi=A1xAvxA2 or gm1xro1xAvxgm2xro2
best regards,
aamar
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