Thanks loose-electron & raja.cedt for your replies.
@loose-electron
Quote:Treat it as Id and don't think like its a transistor anymore.
Or treat it like its a bipolar, and that Vbase = Vcollector and you are d
If I treat this way i.e. if I reduce BJT to two terminals:
- Termial1 = Emittor
- Termial2 = Collector + Base
Hence the diode current 'Id' becomes
Id = IE = IC+IB = Is * exp(qVBE/kT)
please correct me if I am wrong.
@ raja.cedt
Quote:it is Ic only, just derive from device physics basics
sir, i am bit out of touch with the device physics. Could you please explain it to me conceptually/intuitively or at least methodology of derivation in brief?
Quote:Considering how high beta is, is it really important anyhow?
But for CMOS technologies 'beta' is only in single digits, right?
Regards
ipsc