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Question on FB (Read 15428 times)
loose-electron
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Re: Question on FB
Reply #15 - Nov 06th, 2011, 5:25am
 
Simplify the thinking a little here:

OP2 and its attached circuitry do not matter.

Why? Its a fixed positive gain.

Thats like saying the first op-amp has a bit more gain in it, and noting else beyond that.

Analyze it from there.
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raja.cedt
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Re: Question on FB
Reply #16 - Nov 6th, 2011, 6:00am
 
hello loose electron,
you are corect, but it adds adds Phase also.

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raj.
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Re: Question on FB
Reply #17 - Nov 7th, 2011, 12:21am
 
The second opamp has local feedback. In general that means less gain and a high frequency pole. The latter means that it most likely won't be dominant. So you don't really need to consider the 'phase'.
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Re: Question on FB
Reply #18 - Nov 7th, 2011, 12:25am
 
hello alex,

I think you have to consider phase also because you said high  okay but how high compared to wp1..otherwise could you please tell me the relations between both UGB's

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Raj.
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Re: Question on FB
Reply #19 - Nov 7th, 2011, 12:38am
 
Of course, Raja.cedt is right in saying that the second opamp matters.
Contrary to loose-electron's statement ("fixed gain") the second opamp strongly influences the stability of the two-opamp combination (called "composite amplifier") due to its phase shift.
In this regard, the GBW of the second opamp as well as both resistor ratios are of importance. A simple ac simulations can reveal the problem areas.
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Re: Question on FB
Reply #20 - Nov 7th, 2011, 12:59am
 
well raja. By broad banding your second opamp its pole moves up. That's the only thing we can tell. How much that is the question, and as we have no details, it's difficult to judge whether it is going to be dominant or not. I agree, and although I suspect it is not of importance, it can go either way...
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Re: Question on FB
Reply #21 - Nov 7th, 2011, 2:19am
 
Lex wrote on Nov 7th, 2011, 12:59am:
well raja. By broad banding your second opamp its pole moves up. That's the only thing we can tell. How much that is the question, and as we have no details, it's difficult to judge whether it is going to be dominant or not. I agree, and although I suspect it is not of importance, it can go either way...


I don't think that it is a question of "dominance"! The effect is simply that the frequency response of the second stage (with feedback) adds to the response of the open-loop gain of the 1st opamp.
Thus, this results in a composite opamp combination that has (at least) two poles within the active region. For a good phase margin the overall feedback should be sufficiently small - resulting in a relatively high overall gain. As mentioned already - details depend on resistor ratios and opamp properties (GBW in particular).
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Re: Question on FB
Reply #22 - Nov 7th, 2011, 2:34am
 
buddypoor wrote on Nov 7th, 2011, 2:19am:
....

I don't think that it is a question of "dominance"! The effect is simply that the frequency response of the second stage (with feedback) adds to the response of the open-loop gain of the 1st opamp.
Thus, this results in a composite opamp combination that has (at least) two poles within the active region.

...


I underlined some words in your reply. The first sentence I agree. The second sentence can be true, but doesn't have to be. So the word 'thus' is out of place, in my opinion. If you replace 'thus'  by 'for example' it'd be fine =)
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Re: Question on FB
Reply #23 - Nov 7th, 2011, 3:37am
 
Hi Alexander,

I suppose you are somewhat more familiar with the secrets of the english language than I am. Thus, I agree with you.
However, for a reasonable design (that makes sense) and for a second opamp with a GBW that is not much larger than that of the 1st opamp there will be a 2nd pole in the active region of the resulting opamp combination.
Don`t forget, the composite opamp should have better properties (more gain for higher frequencies) if compared with a single opamp. Otherwise the whole combination makes no sense. Of course, I can give the 2nd opamp with feedback a gain of 0 or perhaps 6 dB. But, where is the improvement?  
Therefore, the 2nd opamp should provide an additional gain of - let's say - at least 12...20 dB. And if its own GBW is not larger at least by a factor of 10 (compared to opamp 1) there will be a second pole within the active region of the combination.
Don't you agree?  
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Re: Question on FB
Reply #24 - Nov 7th, 2011, 4:10am
 
In this context (properties of a composite two-opamp combination) it is perhaps worth mentioning that many, many papers have been published in the past dealing with methods (active, passive) to stabilize such circuits - for amplifier as well as for integrator applications.
These methods are summarized under the name "active/passive phase compensation".
By the way: A very detailed treatement of 4 different methods to combine two opamps with the aim to extend the usable frequency range was published already in 1987 by Mikhael and Michael:
(Composite operational amplifiers: Generation and finite-gain applications, IEEE Transactions Circuits & Systems, CAS34, No.5, may 1987)
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Re: Question on FB
Reply #25 - Nov 7th, 2011, 6:54am
 
buddypoor wrote on Nov 7th, 2011, 3:37am:
Hi Alexander,

I suppose you are somewhat more familiar with the secrets of the english language than I am. Thus, I agree with you.
However, for a reasonable design (that makes sense) and for a second opamp with a GBW that is not much larger than that of the 1st opamp there will be a 2nd pole in the active region of the resulting opamp combination.
Don`t forget, the composite opamp should have better properties (more gain for higher frequencies) if compared with a single opamp. Otherwise the whole combination makes no sense. Of course, I can give the 2nd opamp with feedback a gain of 0 or perhaps 6 dB. But, where is the improvement?  
Therefore,.....


Well first of all, the second opamp might have other features than gain. Say for example a good driving capability or so. You could mix a low noise opamp with a low distortion opamp in this way.

But assuming that the second opamp would purely be used for gain, why placing the local feedback at all? To me it would seem better to get rid of that local feedback (find a way of preserving the negative sign), and use some decent frequency compensation, e.g. placing a capacitor in parallel with the resistor in the fb network (i.e. placing a zero in the fb). Much more efficient, imho.

Thx for the info. I will take a look at it some time. =)
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Re: Question on FB
Reply #26 - Nov 7th, 2011, 8:11am
 
hello buddypoor,
thanks for such a nice pap.

Thanks,
raj.
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Re: Question on FB
Reply #27 - Nov 7th, 2011, 10:12am
 
Hi Alexander,

Qote: Well first of all, the second opamp might have other features than gain. Say for example a good driving capability or so. You could mix a low noise opamp with a low distortion opamp in this way.

Yes, I agree with you. More gain - and thus - hopefully more bandwidth is only one of several possible reasons. For example, often the second opamp is replaced by a current feedback amplifier because of its good slew rate properties.

Quote: But assuming that the second opamp would purely be used for gain, why placing the local feedback at all? To me it would seem better to get rid of that local feedback (find a way of preserving the negative sign), and use some decent frequency compensation, e.g. placing a capacitor in parallel with the resistor in the fb network (i.e. placing a zero in the fb). Much more efficient, imho.

I doubt if this is really a good suggestion. If this would be true, you could compensate each opamp with 2 poles in the active region using such a parallel capacitor. Or do you speak about two completely different opamps with different GBW's?
But I know several other composite configurations that have similar (or even better) properties. Some are treated/investigated in the mentioned article (and eqipped with stabilizing features).
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Re: Question on FB
Reply #28 - Nov 7th, 2011, 12:58pm
 
Short of special characteristics the second opamp is not needed.

If its chip level, that second set of "special" properties can be put into the first opamp.

Second order effects like additional noise, additional phase, (and a bunch of other things) are not even being considered here.

Just the basic architecture.

If you want to get into he relative pole placement of things, additive phase, additive noise figure, contributions of offset and systematic mismatches etc etc etc etc you are going to need a lot more details to define it.

Whet was described in the original question can be done with a single opamp.
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Re: Question on FB
Reply #29 - Nov 7th, 2011, 1:00pm
 
Also, if you want a special output stage, close the feedback path with that device in the feedback loop, that way the high gain of the opamp gets used to maintain linearity of the output device.
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