aaron_do
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Hi,
The input noise power will get split in the same way that the signal power is split. The splitter itself has no knowledge of what is being fed into it.
The splitter is a passive component, so the noise that it adds is only related to its insertion loss. This could be small depending on the splitter you are using. For an ideal power splitter, you can assume that no noise is added.
If you are talking about a non-ideal power splitter, then I would have to think about it a bit more. Your equations look to be correct, but how they really work out is a bit unclear since in reality, G1 and Na are related as noise factor is normally equal to insertion loss (for a passive component). I would start with that fact and then simply divide the noise power and signal power 4 ways.
regards, Aaron
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