The Designer's Guide Community
Welcome, Guest. Please Login or Register. Please follow the Forum guidelines.
Jun 13th, 2021, 1:43am
Pages: 1
Send Topic Print
why bang-bang PD need not a charge pump (Read 2718 times)
New Member

Posts: 1

why bang-bang PD need not a charge pump
Oct 18th, 2012, 2:53am
"BBPDs(bang-bang phase detector) typically provide so much gain as to avoid the use of charge pumps, thus obviating the need for amplification of very short pulses"
quoted from the paper "Analysis and Modeling of Bang-Bang Clock and Data Recovery Circuits"

Is this mean that the utility of a charge pump is to generate a longer pulse ?

or a higher PD gain means a longer pulse output?

so what's the relationship between the gain of a PD and time domain pulses generated by the PD?
Back to top
View Profile   IP Logged
Pages: 1
Send Topic Print
Copyright 2002-2021 Designer’s Guide Consulting, Inc. Designer’s Guide® is a registered trademark of Designer’s Guide Consulting, Inc. All rights reserved. Send comments or questions to Consider submitting a paper or model.