raja.cedt wrote on Feb 26th, 2013, 7:44am:hello,
@robg: i forgo to ask, can you please explain how it will be useful for sensing power supply variations?
Thanks,
Raj.
Oh, I was joking, which maybe I shouldn't do since I could be taken seriously. As far as I can tell the positive feedback will force the output to the positive rail or the negative rail so the output will Vss or Vdd-Vgs. In other words, it is a measure of the power supply.
Maybe Rd is small enough that it will find an operating point, but in that case the M1 bias current will be (Vdd-(Vo+Vgs3)) so it will be dependent on Vdd.
I could be wrong, but I can't see how it would work.
Did you get the email I sent you?