baab
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Thank you, Raja and sorry for the late reply. I still has two questions I am confused. 1. In your answer, the voltage above VDD is Vp/π. I can't figure out why Vp = Ip*Rp* 2√2 Can you tell me why? 2. Can you tell me why the voltage at points X, Y (Drains of M1 and M2) has the shape like that? I think it should be a sinosoid but not. Here is my thought: Vx = VDD - VL Where VL is the voltage across half of primary winding. VL = Ldi/dt With ID1 has the shape said above, then Vx has to be a sinosoid. Can you tell me where I am wrong?
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