As described in

http://www.designers-guide.org/Modeling/ind.pdf, you model skin effect in an inductor by adding an additional impedance in series with your inductor. The details of this additional impedance is affected by the physical geometry of the inductor, but it in most cases it is well approximated by:

*Z*(

*f*) = √(j

*f*) = √(2

*f*) (1 + j)/(2

*H*)

You can further break this down in to resistive and reactive components:

*Z*(

*f*) =

*R*(

*f*) +

*X*(

*f*)

*R*(

*f*) = √(2

*f*)/(2

*H*)

*X*(

*f*) = j√(2

*f*)/(2

*H*)

From the first equation, you can clearly see that the resistance increases with √

*f*. Clearly so does the reactance. But if we model the reactance as an inductance:

jω

*L* =

*X*(

*f*) = j√(2

*f*)/(2

*H*)

*L* = √2/(4πH√

*f*)

So while the reactance due to the inductive part of skin effect is increasing with frequency, the actual extra inductance decreases with frequency.

-Ken