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Insertion Loss (Read 763 times)
Marios
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Insertion Loss
Jul 16th, 2020, 5:22am
 
Dear all,

I have a question with regards to insertion loss definition.

Is it IL = (power delivered to load) / (power absorbed by our DUT)
or    IL = (power available from DUT) / (power absorbed by out DUT)

Regards
Marios
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Horror Vacui
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Re: Insertion Loss
Reply #1 - Aug 2nd, 2020, 6:57am
 
Insertion loss does not care about whether a good power match is present at the other end. It is general.

Insertion loss assumes that you already have a circuit and you insert something into it. Typically a two port component. The ratio of the powers at the desired point in the system is the insertion loss.

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