Paul
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Hi boa,
personnally I would use the first method, obtaining the switches on-resistance as the ratio between the small Vds voltage (e.g 100mV) and the current flowing through this Vds voltage source. You don't need the capacitor as you are doing a DC sweep.
Notice that the on-resistance depends a lot on the voltage applied with respect to ground (the swept DC voltage). To be sure your design will work, you should take the worst-case resistance inside your useful signal swing. The signal swing may depend on the place of the switch in the schematic.
Paul
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