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The Designer's Guide Community Forum › Design › Analog Design › linear time-based events in verilog-ams
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linear time-based events in verilog-ams (Read 2244 times)
steve_mac
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linear time-based events in verilog-ams
Nov 23rd, 2005, 3:42am  
hi i'm new with verilog-a and i'd like to ask how do i model a linear time-based event ?

example:  a linear voltage drop :

                            V = -3.4545 * time + Vdd

How do i put the "time" here in verilog-a syntax?

Thanks, appreciate the help.
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Jess Chen
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Re: linear time-based events in verilog-ams
Reply #1 - Nov 23rd, 2005, 9:57am  
Try

V = -3.4545*$abstime + Vdd.

If you want incremental time, you can use

t = idt(1,0,assrt).

When assrt is nonzero, t remains at zero. When assrt is zero, t = incremental time. The only caution is that depending on the application, you may have to use conservative numerical options.

-Jess
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steve_mac
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Re: linear time-based events in verilog-ams
Reply #2 - Nov 23rd, 2005, 6:44pm  
Hi Jess,

Thanks Smiley
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