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regarding DAC THD (Read 2125 times)
venki_vlsi
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warangal
regarding DAC THD
Jun 10th, 2007, 8:20pm
 
hi,
i calculated my THD by keeping a fourier component at output.
Conditions : FIn=10.1318MHz,FS=125Mhz,Cycles=83,Samples=1024.
I have plotted 512 hormonics by giving normhorm=83,hormonics=512,Fund=122.07Khz and found THD=57db.
In that 512 hormonics i taken out  5 hormonics (83,83*2,83*3,83*4,83*5)and calculated THD=63.15db.
now my doubt is whether these 512 hormonics includes THD+transient noise+thermal noise,or its only THD(hormonic components).
If it is THD+noise,is it  equal to SNDR of DAC.
SNDR=S/N+THD.
Most of papers are specifying only 1st ,2nd 3rd,4th,and 5th hormonic output as THD but here we r including all frequencies till Fs/2.That the reason i got this doubt

Regards
venkats

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s.venkat_nitw
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ywguo
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Shanghai, PRC
Re: regarding DAC THD
Reply #1 - Jun 19th, 2007, 7:13pm
 
Hi, Venkats,

I think that the THD reported by fourier component is SNDR (THD + SNR) actually. Since usually we don't include transient noise for input signal or sampling clock, the resultant SNR is normally quatization noise only.  

To compare with other works/papers, we have to calculate THD specifying the number of harmonics.


Best regards,
Yawei
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