babunp114525
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Posts: 5
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hi ywguo,
you are right that while calculating the DNL, offset is nullified as DNL = Tp[i+1] - Tp[i]. Now, here Tp[i+1] and Tp[i] are having same amount of offset. Therefore, while measuring DNL, offset is getting nullified.
But DNL is present at each and every code. Therefore, can I write Tp[1] = 1LSB width+DNL+Offset?
if this is true, then we need to consider the DNL value while considering the offset, else not. But, I am not sure whether, the above equation is right?
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