aaron_do wrote on Nov 30th, 2007, 1:45am:Hi,
input referred noise is just the output noise power divided by the power gain. If you measure the output noise is V^2/Hz, and you want to refer it back to a voltage, divide by (V/V)^2. If you measure in terms of output current ^2 then divide by gm^2. Your 50 ohm resistor is just complicating things since you don't need it to find the input referred noise (unless its part of the circuit). In fact you have to subtract its noise contribution to find the input referred noise. For example, if you have a port and you measure NF, the IRN can be found from,
NF=(IRN+kT50)/kT50
where IRN is in V^2/sqrt(Hz)
hope it helps,
Aaron
Hi, Aaron:
thank your for your information.the reason of adding the resistor is that, I just want to see the relationship of these three quantities, as spectre reference sais, when input port is used as input probe, the noise associated with the port resistance will contribute to the total output noise, so I intentionally add resistors in two other situations to equate the noise source number in the circuit. and i expect that if we ignore the correlation btw the noise voltage and noise current, the following relation may hold:
N_current^2*50^2+N_voltage^2 = N_port^2
but i can not arrive at this relation from the simulation result. So I asked the question.
Any other information?