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derive the transfer function from fully-diff cir. (Read 2557 times)
trashbox
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derive the transfer function from fully-diff cir.
Jan 07th, 2008, 1:17am
 
Hi all,
I am studying a fully-diff circuit and wanna derive the transfer function from the attached circuit, would you please give me any hints or formulas? Thanks.
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Berti
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Re: derive the transfer function from fully-diff c
Reply #1 - Jan 7th, 2008, 11:55pm
 
hmmm, just use nodal analysis. You will get a system of equations which you can solve for
the output (voutp-voutm) and divide by the input (vinp-vinm) in order to obtain the transfer
function.
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trashbox
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Re: derive the transfer function from fully-diff c
Reply #2 - Jan 10th, 2008, 1:46am
 
Hi Berti
Thanks. I have solved  this problem.
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HdrChopper
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Re: derive the transfer function from fully-diff c
Reply #3 - Jan 14th, 2008, 12:10pm
 
Hi

You can easily derive it by finding using thevenin equivalent circuits. You can use the concept of hemi-circuit, based on the fact you are analyzing a fully diff (purely symmetrical circuit).
If you split the input circuit (Z1/Z3/Z1), you'll get a simple resistor divider equal to Z3/2÷(Z3/2+Z1). That is the input impedance of your input voltage source.
Z2 does not play a role in the transfer function assuming the op amp's input impedance is >> Z2.

From this you get H=-(Z4*(Z3/2 + Z1)) / (Z3/2)

Hope this helps
Tosei
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Keep it simple
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