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I/Q mismatch (Read 2345 times)
yhq0413
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I/Q mismatch
Jan 16th, 2008, 1:26am
 
hi
I do not know how to compute the I/Q mismatch?
for example
IP IN QP QN
amplitude(mv) 193 193 190 190

phase(°) 0 92 182 270

the amplitude mismathc is 3mv, is 3db?
the phase error is 2°?
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ACWWong
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Re:  I/Q mismatch
Reply #1 - Jan 16th, 2008, 3:24am
 
Hi yhq0413,

I would say the IQ phase error is 2o (assuming you have mixed up 92 with 182 in your phase list). I guess the phase numbers you give would also suggest that the is a non 50:50 duty cycle (slight error in mark/space ratio) on the output differential I and Q.

The IQ amplitude mismatch would be 0.136dB. (20*LOG10[193/190]). That is I is 0.136dB larger than Q in your case.

Often I use differential I and differential Q at the component of frequency of interest (available from pss analyses) to get the IQ mismatch rather than transient simulation and markers on waveforms.

cheers
aw
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« Last Edit: Jan 16th, 2008, 6:52am by ACWWong »  
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yhq0413
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Re:  I/Q mismatch
Reply #2 - Jan 16th, 2008, 10:42pm
 
thanks Smiley
I use the PSS  to evaluate the I/Q mismatch
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