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CPPLL unit (Read 2371 times)
newic
Senior Member
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Posts: 138
CPPLL unit
Jul 12
th
, 2010, 3:27am
I want to confirm the units of each component for a CPPLL
input=phi_error (rad)
Phase detector + CP : Icp/2pi (A/rad)
LPF: impedance (ohm)
VCO: 2pi*Kvco/s (rad/V)
output of VCO clk: rad*(A/rad)*(ohm)*(rad/V)= rad
is it correct?
should the VCO gain be Hz/V or rad/V?
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Mayank
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Posts: 334
Re: CPPLL unit
Reply #1 -
Jul 13
th
, 2010, 1:43am
2*pi*f = ω(angular velocity) where f is in Hz & ω is in rad/s.
Hence 2*pi* x Hz/V = y rad/V.
Units of Kvco are Hz/V & hence, 2*pi*Kvco translates it to rad/sec/V.
Integrating this i.e. multiplying by (1/s) in Freq. Domain yields rad/V.
--M
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