HI Raja,

Q for a inductor/capacitor is always defined as  magnitude of reactive part/resistive part, so it always comes down when the series resistance increases regardless of whether it is capacitive or inductive.

when you have a series resistance with the inductor or capacitor, it has to be converted to its parallel equivalent and the parallel equivalent is used to calculate the resonant frequency via w=1/sqrt(LC).

For an inductor, with a series resistance, the parallel inductance value increases and is given by (w^2.L^2+R^2)/(w^2.L) where R and L are the series resistance and inductance. Hence the resonant frequency comes down.

For the capacitor, the parallel capacitance value decreases and hence the resonant frequency increases.