vp1953
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HI Raja,
Q for a inductor/capacitor is always defined as magnitude of reactive part/resistive part, so it always comes down when the series resistance increases regardless of whether it is capacitive or inductive.
when you have a series resistance with the inductor or capacitor, it has to be converted to its parallel equivalent and the parallel equivalent is used to calculate the resonant frequency via w=1/sqrt(LC).
For an inductor, with a series resistance, the parallel inductance value increases and is given by (w^2.L^2+R^2)/(w^2.L) where R and L are the series resistance and inductance. Hence the resonant frequency comes down.
For the capacitor, the parallel capacitance value decreases and hence the resonant frequency increases.
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