Geoffrey_Coram
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It's basic Spice theory -- ac analysis linearizes the circuit, and the current is I = (G + sC) V, where V is the ac magnitude of your source, s is the Laplace frequency -- usually s = jω -- and I is the current you measure in your source. v1 1 0 3.3 ac 1 is a Spice voltage source from node '1' to ground, dc voltage is 3.3, ac magnitude is 1. Note that the current you measure is ω times the capacitance.
You should try this with a plain linear capacitor and verify this.
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