The Designer's Guide Community
Forum
Welcome, Guest. Please Login or Register. Please follow the Forum guidelines.
Jul 16th, 2024, 7:31pm
Pages: 1
Send Topic Print
Class E power amplifier (Read 2322 times)
baab
Senior Member
****
Offline



Posts: 178
EA
Class E power amplifier
Aug 27th, 2013, 7:41pm
 
Hi,
Please help me with these questions about class E power amplifier. Thanks.



http://imageshack.us/f/62/u9dr.jpg/
http://imageshack.us/f/21/umgr.jpg/
http://imageshack.us/f/14/jat9.jpg/
Back to top
 
 
View Profile   IP Logged
aaron_do
Senior Fellow
******
Offline



Posts: 1398

Re: Class E power amplifier
Reply #1 - Aug 27th, 2013, 8:20pm
 
Hi,


for the dV/dt part neat zero, I think the author is simply saying that if there is a time shift (such that there is overlap), you don't want a large change in voltage as this would result in power being burnt in the transistor. i.e. change in voltage / change in time should be zero.

The RFC has an average voltage drop across it of 0 V. When the transistor is ON, VX will be pulled down to ground making the voltage drop across it equal to VDD. In order for the average voltage drop across the RFC to be zero, when the transistor turns OFF, VX rises above VDD. In fact for the class-E PA I believe it is above 2*VDD, but I can't remember the theoretical number.

An ideal RFC provides a constant current (not voltage) because its AC impedance is infinite or dI/dV = 0.


Aaron
Back to top
 
 

there is no energy in matter other than that received from the environment - Nikola Tesla
View Profile   IP Logged
baab
Senior Member
****
Offline



Posts: 178
EA
Re: Class E power amplifier
Reply #2 - Aug 28th, 2013, 10:28pm
 
Thank you, Aaron and sorry for the inconvenience. I can't figure out how to attach images by using " [img][/img]".
Quote:
for the dV/dt part neat zero, I think the author is simply saying that if there is a time shift (such that there is overlap), you don't want a large change in voltage as this would result in power being burnt in the transistor. i.e. change in voltage / change in time should be zero.

When the transistor is OFF, Vx will increase but it can't increase suddenly because of the presence of the capacitor C1.
We need dVx/dt = 0 around the time transistor switches from ON to OFF. According to second condition the desired value of Vx is the smallest.
Then, apply both second and third conditions, we need Vx at the time when transistor switches from ON to OFF is very very small. Is this right that the voltage Vx is very small at the time transistor switches from ON to OFF?



Back to top
 
 
View Profile   IP Logged
Pages: 1
Send Topic Print
Copyright 2002-2024 Designer’s Guide Consulting, Inc. Designer’s Guide® is a registered trademark of Designer’s Guide Consulting, Inc. All rights reserved. Send comments or questions to editor@designers-guide.org. Consider submitting a paper or model.