Jeffrey987
Junior Member
Offline
Posts: 26
|
The jitter on the clock causes the SNR to drop. It all depends on the slew rate of your sampled signal. Assume a sine of frequency f0, sampled at fs.
the slew rate at any time t is w0 A cos( w0 t). Since the variance on the time is converted to a variance in voltage via this slew rate. The voltage noise increases as the slew rate increases (high f signals). If your signal is uncorrelated with the clock, then you have to integrate the noise over the entire phase (0-2pi) because the slew rate is phase dependent. If your signal is correlated with the clock, you have to take into account this correlation.
|