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Diffamp (Read 4488 times)
raja.cedt
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Diffamp
Sep 25th, 2009, 9:41am
 
hi,
  while reading differential amplifiers i found 4 gains (differential to differential, common mode to differential, common mode to common mode,differential to common mode)..i didn't understand theoretically how differential mode will be converted into common mode

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Rajasekhar.
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cczhang
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Re: Diffamp
Reply #1 - Sep 27th, 2009, 2:02am
 
HI,generally speaking, differential opamp has common mode feedback circuit, and there will be mismatch between mosfets, so there will be four gains
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raja.cedt
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Re: Diffamp
Reply #2 - Sep 27th, 2009, 8:49am
 
hi,
   could you please explain clearly..

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Rajasekhar.
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HdrChopper
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Re: Diffamp
Reply #3 - Sep 27th, 2009, 9:07am
 
Hi Rajasekhar,

Itīs simple: just imagine a resistive loaded diff pair with a purely differential signal, and assume a mismatch on the load resistor.
The single ended output signals will not be perfectly centered around the nominal CM since both are different (non-symmetrical) due to the resistorīs mismatch.
Thus you generated a CM output signal by ONLY applying a differential signal.

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Tosei
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raja.cedt
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Re: Diffamp
Reply #4 - Sep 28th, 2009, 9:49pm
 
hi,
   thanks for your ans, i have understand your ans like the following. Due to mismatch in resistor output voltages are not perfect differential, so you can divide them into differential and common mode. Correct me if am wrong.

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rajasekhar.
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cczhang
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Re: Diffamp
Reply #5 - Sep 29th, 2009, 12:26am
 
raja.cedt wrote on Sep 28th, 2009, 9:49pm:
hi,
   thanks for your ans, i have understand your ans like the following. Due to mismatch in resistor output voltages are not perfect differential, so you can divide them into differential and common mode. Correct me if am wrong.

Thanks,
rajasekhar.


Hi,maybe this paper will help you understand the gains.

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raja.cedt
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Re: Diffamp
Reply #6 - Sep 29th, 2009, 1:13am
 
hi cczhang,
                 thank you very much for the paper.

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Rajasekhar
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HdrChopper
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Re: Diffamp
Reply #7 - Sep 29th, 2009, 7:12pm
 
raja.cedt wrote on Sep 28th, 2009, 9:49pm:
hi,
   thanks for your ans, i have understand your ans like the following. Due to mismatch in resistor output voltages are not perfect differential, so you can divide them into differential and common mode. Correct me if am wrong.

Thanks,
rajasekhar.



That's correct Rajasekhar.

Regards
Tosei
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