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The Designer's Guide Community Forum › Design › RF Design › what is the physical meaning of Φ(s) in pll
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what is the physical meaning of Φ(s) in pll (Read 3450 times)
Hejia
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what is the physical meaning of Φ(s) in pll
Jan 15th, 2016, 6:27pm  
When designing a PLL, we will try to get the closed-loop transfer function:
H(s)=Φout(s)/Φref(s).
I can't really understand the physical meaning of the Laplace Domain interpretation of phase.
For example, what does |Φ(jw)| mean? The magnitude of phase at different frequency? It just doesn't make any sense to me.
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loose-electron
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Re: what is the physical meaning of Φ(s) in pll
Reply #1 - Jan 16th, 2016, 9:57pm  
IF I am not mistaken -

First one is static phase error, input to output.

The other one is phase error as a function of frequency, where if the reference frequency coming in is changed, the phase error changes as a function  of that reference frequency.

I think that is what you are looking for?
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Jerry Twomey
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Hejia
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Re: what is the physical meaning of Φ(s) in pll
Reply #2 - Jan 18th, 2016, 10:22am  
Thanks, Jerry.

Your reply really gives me some useful thinking toward my question. Grin
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Re: what is the physical meaning of Φ(s) in pll
Reply #3 - Jan 21st, 2016, 8:29pm  
happy to help
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Jerry Twomey
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